Find two positive numbers satisfying the given requirements. the product is 156 and the sum is a minimum.

156 = 2*2*3*13

Product: Sum:

1) 156 = 2*78 2+78 =80

2) 156 = 4*39 4+39=43

3) 156=12*13 12 +13 =26

4) 156 = 6*26 6+26 = 32

The numbers are 12 and 13, because their product is 156, and their sum is minimum of possible.

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet