Find the probability that when a couple has fourfour children, at least one of them is a girlgirl. (assume that boys and girls are equally likely.)

A - at leats one is a girl

B - none is a girl

This is a case of binomial probability, with n=4 and p=0.5.

Note that P(at least one of the four children is a girl) = 1 - P(no girls among 4 children).

P(no girls among 4 children) = binompdf(4,0.5,0) = 0.0625

Then P(at least one of the four children is a girl) = 1 - 0.0625 = 0.94.

2

step-by-step explanation:

because 1.2 isnt half of 6 duh