Ron finley is a gardener who decided a few years ago to plant several gardens in south central los angeles. he wants his next garden to be a rectangle where the length is three times the width. additionally, it must have a perimeter of 24 yards because of space constraints. what are the length and the width of the garden?

Well, we can be sure that whatever the width is, we can call it ' W '. Then, from information in the question, the length of the garden is ' 3W '.

Now, the perimeter of a rectangle is (length + width + length + width). Using the fancy algebra labels I just gave them, that's (3W + W + 3W + W). And now I can go through that, add up all the Ws, and get a total of 8W for the perimeter.

But he question tells us that the perimeter is 24 yards, so 8W = 24 yds.

Divide each side of that equation by 8, and we discover that W = 3 yds. And if THAT's true, then 3W = 9 yds. Bada bing ! We have the dimensions of the garden.

It's 3 yards wide and 9 yards long.

first, we define the variables:

x: number of years after 1950

f (x): amount of vinyl sold.

then, with the variables defined, we have:

68594 vinyl records were sold in 1958 > f (8) = 68594

91299 vinyl records were sold in 1961 > f (11) = 91299

38720 vinyl records were sold in 1952 > f (2) = 38720

161743 vinyl records were sold in 1967 > f (17) = 161743

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step-by-step explanation: