If the sum of the first two consecutive even integers is equal to three times the third what are the three integers?

we are given

three consecutive even integers

Let's assume

first even integer is x

second even integer is x+2

third even integer is x+4

sum of the first two consecutive even integers is equal to three times the third so, we can get equation as

now, we can solve for x

so, we get

first integer is -10

second integer is -10+2=-8

third integer is -10+4=-6.................Answer

2

step-by-step explanation:

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐