Answers: 1
is non-negative and requires that 
in order to be defined, while 
when 
. This means we can only find real solutions in the range 
.
, which is larger than 4, so we omit that solution. Then 
is the only solution.
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What are the beginning steps of solving this? [tex]2x + \sqrt{x + 1} = 8[/tex]...
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