Factor 2x2 − 10x − 48 completely. a 2(x − 3)(x + 8) b (2x + 3)(x − 8) c (2x − 3)(x + 8) d 2(x + 3)(x − 8)

Alright, lets get started.

The given expression is :

Firstly, we could take 2 as common factor out

-5x could be written as -8x + 3x

Now, taking x common factor out in first two terms and 3 common factor in last two terms

or

Answer is option d.

Hope it will help :)

the answer is 489

step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)