Mr. albano wants to paint menus on the wall of his cafe in chalkboard paint. the gray area below shows where the rectangular menus will be. each menu will measure 6ft wide and 7 1/2 ft tall. how many square feet of menu space will mr. albano have? what is the area of wall space that is not covered by the chalkboard paint?

Given:

Whole wall is 13 2/3 ft by 25ft

4 menus (gray areas) with measurements of 6 ft wide and 7 1/2 ft tall.

Convert mixed fractions into improper fractions.

13 2/3 ft = ((13*3)+2)/3 = 41/3

Area of the Wall = 41/3 ft * 25 ft = (41*25)/3 = 1025/3 ft² = 341 2/3 ft²

7 1/2 ft = ((7*2)+1)/2 = 15/2

Area of the menu = 15/2 ft * 6 ft = (15*6)/2 = 90/2 = 45 ft²

45 ft² x 4 menus = 180 ft²

Area of wall space not covered by the chalkboard paint:

A = 341 2/3 ft² - 180 ft² = 161 2/3 ft²

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