Use point-slope form, y - y1 = m(x - x1), to find the linear equation of a line that passes through the points (2, -1) and (10, 7).

y = x - 3

Step-by-step explanation:

Find the change in x as we move from (2, -1) to (10, 7); it is 8.  This is the 'run.'

Similarly, the change in y is 8.

Thus, the slope of the line through these two points is m = rise/run = 8/8, or 1.  The slope of this line is m = 1.

Arbitrarily using the coordinates of the point (2, -1), along with the point-slope formula y = mx + b, we get:

-1 = 1(2) = b, so that

-3 = b

and so the desired equation of the line passing through these two points is

y = 1(x - 3), or simply y = x - 3