Anybody know the proper answer to this in au? ?

It depends if that angle is in degrees or radians; let's assume radians because then there's a trick.

If we draw the line from the star to the sun, we have a right triangle, angle .000302/2, opposite 1 AU and hypotenuse x the distance we seek.

The trick is for really small angles the sine is (approximately) equal to the angle in radians:

Let's see if our approximation made a difference in the last digit:

Nope, no difference to six sig figs.

6623

nope

step-by-step explanation: