Graph the system of inequalities. then use your graph to identify the point that represents a solution to the system. x < 2 and y ≤ 4x + 1 (5, 6) (5, –2) (–3, –15) (1, 11)

y = 4x + 1

for x = 0 → y = 4(0) + 1 = 1 → (0, 1)

for x = -1 → y = 4(-1) + 1 = -3 → (-1, -3)

Look at the picture.

(-3, 15)

7

step-by-step explanation:

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.