If y = x+2 were arranged to y= x+1, how would you graph the new function compare with the first one

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

let m = monomial

let t = trinomial

so, m times t = t.

monomial times a trinomial = another trinomial.