If someone could with this one 2 it would be greatly appreciated

Given recursive formula is

f(n) = 22 * f(n - 1)

Where first term : f(1) = 10

And we need to find the first five terms of this sequence. So , let's find the second term by plug in n = 2 in the above formula. Therefore,

f (2) = 2.2 * f ( 2 -1)

= 2.2 * f(1)

= 2.2 * 10

= 22

So second term is 22.

Similarly plug in 3 for n to get the third term. Hence,

f(3) = 2.2 * f(3 -1) = 2.2 * f(2) = 2.2 * 22= 48.4

f(4) = 2.2 *f( 4 -1) = 2.2 * f(3) = 2.2* 48.4 = 106.48

f(5) = 2.2* f(5-1)= 2.2 * f(4) = 2.2 * 106.48 = 234.256

So, the first five terms are 10, 22, 48.4, 106.48 and 234.256.

Hope this helps you!

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