If two or more polygons are congruent, which statement must be true about the polygons? read all of the choices before deciding. a. pairs of corresponding angles have the same measure. b. pairs of corresponding sides have the same length. c. the polygons are parallelograms. d. the polygons are regular. e. rigid transformations can be used to map one polygon onto the other. a. a, b, c, d, and e b. a, b, and e c. a, c, d, and e d. a, c, and e

If two or more polygons are congruent, you can place one on top of the other, and they will match exactly. Congruent polygons do not have to be parallelograms or regular. Options A, B, and E are true.

B. A, B, and E

something that characterises a right triangle is the fact that we may use pythagoras' theorem to find any one of its sides given that we have the length of the other two sides. here, we have the length of the hypotenuse, √(87) yd, and one other side, √(23) yd, thus we can easily find the length of the remaining side using pythagoras' theorem as defined below:

c^2 = a^2 + b^2, where c is the length of the hypotenuse, and a and b are the lengths of the other two sides.

thus, given that c = √(87) and a = √(23), we may substitute these into the formula we defined above to get:

c^2 = a^2 + b^2

(√87)^2 = (√23)^2 + b^2 (substitute c = √87 and a = √23 into the equation)

87 = 23 + b^2 (evaluate (√87)^2 = 87 and (√23)^2 = 23 - remember that the square root of a number, squared will equal that very same number)

64 = b^2 (subtract 23 from both sides)

√64 = b (take the square root of both sides)

8 = b (evaluate √64 = 8)

therefor, the length of the unknown leg in the right triangle is 8 yd (first answer).

its the second choice.

step-by-step explanation:

the elements in the range will be 7 less than the elements in the domain.