Me with this thx plz explain 15 pts

Step One

The first thing to do is make a table of how many letters "A" will go through to get to it's destination. In order to do this,, you need to realize that the angular distance between letters is 36 degrees. So if the center of the circle is O, then AOB = 36 degrees. How did I get that? The figure is a decagon. That means it has 10 equal divisions going from A to J. 360 / 10 = 36 degrees between each letter.

Angle Positions Moved

2527

1083

135 3.75 I can't see how this will be an answer. It is between the 3rd and 4th letters, so there is no letter sitting in that place.

1805

2888

324 9

Step Two

How will A land on D? Start with B. It counts as 1. Now go to C that counts as 2. Finally you hit D on the third angle. For D you put in 108 degrees.

You do each of the other letters the same way. Make up another table

Letter Angle # Steps

D 108 3

F180 5

H2527

I2888

This is a pretty nice little problem.

A regular decagon has 10 sides. The central angle is equally divided into 10, which is 360/10=36 ° between adjacent diagonals.

This also means that a rotation of 36 ° will create an image identical to the preimage, except for letter labels. The order of rotational symmetry is therefore 10, with angles of rotations in multiples of 36 ° .

Thus, A' coincides with B, the rotation angle is 36 °. If A' coincides with C, the rotation is 36*2=72 ° and so on.

So the number of letter spaces between A and the destination letter, multiplied by 36 ° gives the rotation angle, in this case, clockwise, since this is how the letters are numbered.

Back to the question,

Vertex letter spaces angle

D 3 * 36=108 °

F 5 * 36=180 °

H 7 * 36=252 °

I 8 * 36=288 °

are ya tryin to ask something or is this a statement