1/y = -3x/2+ 3 and rewrite it in the form of y = p/ q+x

1/y = -3x /2 + 3

mulytiply each term by 2y:-

2 = -3xy + 6y

y = 2 / -3( (x - 2)

y = -0.667 (-2 + x)

c

step-by-step explanation:

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation: