Which is the equation of a line that has a slope of 1/2 and passes through point (2, -3)?

So for this, I will be making the equation using the slope-intercept form, which is y=mx+b (m = slope, b = y-intercept).

Since we have the slope, 1/2, we can just plug in (2,-3) into the equation and solve for b as such:

Putting everything together, our equation is y = 1/2x - 4.

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

300pi

step-by-step explanation: