Match each function with the corresponding function formula when h(x) = 2 – 2x and g(x) = –2 x + 2. 1. k(x) = (h – 2g)(x) 2. k(x) = (g + h)(x) 3. k(x) = (h – g)(x) 4. k(x) = (2g + h)(x) 5. k(x) = (g – h)(x) 6. k(x) = (2h – 2g)(x)

the correct functions are

h(x) = 3x + 2

g(x) = 2^x

proceed to calculate the different values ​​of K (x)

case 1) k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + 2]> is the option 4.k(x) = 2^(3x + 2 )

case 2) k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+2> is the option 1.) k(x) = 2^x + 3x + 4

case 3)k(x) = g(x) - h(x)

k(x) = [2^x]-[3x + 2]=2^x-3x-2> is the option 2.) k(x) = 2^x - 3x - 2

correct answer:

a + bi

step-by-step explanation: