Me & explain i appreciate it: )

Let's start with what is true. It's B. You need 2 facts to prove that lines are perpendicular when parallel lines with a transversal is involved.

1. You need the The line you want to perpendicular to the transversal and the transversal to form supplementary angles.

2 You want the supplementary angles formed to be equal.

Condition 1 has been met by the fourth step. So it must be condition 2 that you need in step 3. <AFD = <AFE Reason Two angles that are equal to the same angle must themselves be equal.

Now the question becomes why not the others?

A is true, but unnecessary. You are going to end up proving that BC is perpendicular to GH which is not what you want.

C is also true, but you will again end up with an unnecessary step. Where do you go from there?

D You can prove that, but it's going to make the question much longer.

the degrees would remain the same ( the number to the left of the decimal point.

the multiply the decimal by 60 to get the minutes and use the numbers to the left of the decimal point.

then multiply the decimal portion of that by 60 for the seconds and round off as needed.

39 .956652

the 39 remains the degrees.

the minutes = 0.956652 x 60 = 57.39912

the minutes = 57

the seconds = 0.39912 x 60 = 23.95 = 24 ( rounded to nearest tenth)

so 39.956652 = 39 degrees, 57 minutes and 24 seconds

-75.159809

the -75 remains the degrees

the minutes = 0.159809 x 60 = 9.58854

the minutes = 9

the seconds = 0.58854 x 60 = 35.31, rounded to nearest tenth = 35.3 seconds

so -75.159809 = -75 degrees, 9 minutes and 35.3 seconds.

the first coordinate is north or south, since it it positive it is north.

the second number is east or west, because it is negative it is west.

39 degrees, 57 minutes and 24 seconds n

-75 degrees, 9 minutes and 35.3 seconds w