Me fix these incorrect answers (don't forget to explain) i appreciate it: ))

Remark

If you can, draw the original diagram of the line segment AB. Make it about 1 inch long. Some distance away, make a line segment that is about 1.8 inches long and parallel to AB. That is going to be A'B'. Now when you draw A'B' It is going to have the same slope as AB which is - 1

Discussion

Here's the catch to this problem. B is the right angle. Is similarity retained when you dilate from the origin. The answer is yes. See the diagram below. The key to this question is understanding that similarity is retained. It it is, then the slopes are the same

The second thing you have to understand is that the right angle is at B. That mean that AB and BC meet at right angles. That means that the slope of BC is

m1 * m2 = -1

where m1 is the slope of AB and m2 is the slope of BC. But we are told that AB has a slope of -1

Therefore m1 = -1

-1 * m2 = -1

m2 = 1

so BC has a slope of 1. Now for the answer.

If BC has a slope of 1 slope is maintained by similarity, then B'C' has a slope of 1 which is your answer

Problem 2

The length you have given is the length of the Hypotenuse. you are asked for AE.

You need to set up a proportion for this question.

You know the most about the small triangle so start with it

AD / AB = (AD + DE) /(AB + BC)

Givens

AD = 5200

DE = x

AB = 5600

AC = 5600 + 7000 = 12600

Solve

5200/(5200 + x) = 5600 / 12600 Cross multiply

5200 * 12600 = (5200 + x) * 5600 Multiply the left and remove the brackets on the right.

65520000 = 29120000 + 5600x Subtract 29120000 from both sides.

65520000 - 29120000 = 5600x

35400000 = 5600x Divide by 5600 on both sides.

36400000 / 5600 = x

6500 = x

Answer

AE = 5200 + 6500

AE = 11700 <<<< Answer

This should be smaller than 12600 which it is.

nope lol

step-by-step explanation:

0 and 5 minutes

step-by-step explanation:

given that one morning eight buses arrive late by the number of minutes given below:

0 8 2 6 9 2 0 7 8

write these in ascending order

0   0 2 6 7 8 8 9

in the afternoon two more buses arrive at the bus stop say by x and y minutes late.

total number of buses = 10

median = average of 4th and 5th after arranging in ascending order

since 4th entry is 6, the values of x and y should be below 6

also given 0 is the mode so either x or y or both should be 0 because then only 0 gets the maximum frequency and hence mode

thus we have

0 0 0 2 6 7 8 8 9 and another unknown entry which is below 6.

since median is 3.5, we have the unknown entry to be 5 only because then only median =( 2+5)/2

thus the after noon buses were late by 0 and 5 minutes.