Aline passes through the point (4,1) and has a slope of -3/2 . write an equation in slope-intercept form for this line.

y=mx+b is the equation of a line;

m=slope , b= y-intercept

m= -3/2 ; so we have : y= (-3/2)x+b

We are give a set of points which it passes through, we can simply plug them in:

1 = (-3/2)(4)+b (4 is the x and 1 is the y)

We get 1 = -6 +b 7=b

our final equation is : y=(-3/2)x+7

you can first factor out the n to get n(1+5). we know that 1+5 is 6, so we just have 6n.

if im not mistaking its

step-by-step explanation: