What are the zeros of the quadratic function f(x) = 8x2 – 16x – 15? x = –1 – and x = –1 + x = –1 – and x = –1 + x = 1 – and x = 1 + x = 1 – and x = 1 +

8x^2 - 16x - 15 = 0

x = [ -(-16) +/- sqrt((-16)^2 - 4*8*-15) / ] 2*8

= 2.696, -0.696

The zeroes of the given polynomial f(x) are

Step-by-step explanation:

Given : Quadratic function

To find : What are the zeros of the quadratic function?

Solution :

Using quadratic formula of the general equation to get the roots is

Comparing the given quadratic equation,

a = 8, b = -16  and  c = - 15.

Substitute the value in the formula,

Therefore, The zeroes of the given polynomial f(x) are

answer: the correct one is a

step-by-step explanation:

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation: