Aright triangle is removed from a rectangle as shown in the figure. find the area of the remaining part of the rectangle. [area of a triangle = 1/2(b)(h)]
a) 57 sq. inches
b) 57.5 sq. inches
c) 58.875 sq. inches
d) 60 sq. inches

I found the image of this problem.

Rectangle : Length is 10 inches. Width is 6 inches.

The side where the right angle was cut off had a rectangle length of 8.5 inches, and a rectangle width of 4.5 inches.

Area of the whole rectangle = 10 inches * 6 inches
A = 60 square inches.

Measure of the triangle:
base: 10 inches - 8.5 inches = 1.5 inches
height: 6 inches - 4.5 inches = 1.5 inches

Area of the triangle = 1/2 * b * h
A = 1/2 *  1.5 in * 1.5 in
A = 1/2 * 2.25 sq. inches
A = 1.125 sq. inches

Area of the remaining part of the rectangle :

A = 60 sq. inches - 1.125 sq. inches
A = 58.875 sq. inches   CHOICE C.) 58.875 sq. inches

Ab=dc ac=de ad=bce i hope this !