On math problem! first person to answer correctly will get brainliest answer!

In this problem, we are given the defintiion of e, a number you'll see a lot in precalculus and calculus. When we are evaluating, a₁₀, it means that 10 goes in for n. If it's a₂₂₂₂, then 2222 goes in for n. When n gets large enough, the approximation gets closer and closer. Only as we get closer and closer infinity are we closer and closer to the exact number e.

a₁₀ = (1 + (1/10)¹⁰ = 1.1¹⁰ = 2.5937

a₁₀₀ = (1 + (1/100)¹⁰⁰ = 1.01¹⁰⁰ = 2.7048

a₁₀₀₀ = 1.001¹⁰⁰⁰ = 2.7169

a₁₀₀₀₀ = 1.0001¹⁰⁰⁰⁰ = 2.71814

a₁₀₀₀₀₀ = 1.00001¹⁰⁰⁰⁰⁰ = 2.71826

As n gets larger, the approximation gets better.

the answer is c

hope this !

answer is : muchas/tipicas

have a nice day!

~recklesschicken