Check my work: write the integral in one variable to find the volume of the solid obtained by rotating the first‐quadrant region bounded by y = 0.5x^2 and y = x about the line x = 5. v = ∫[0,2] 2πrh dx r=5-x and h=x-x^2/2 v = ∫[0,2] 2π(5-x)(x-x^2/2) dx = 16π/3 v = ∫[0,2] π(r^2-r^2) dy r=5-y and r=5-√(2y) v = ∫[0,2] π((5-y)^2-(5-√(2y))^2) dy = 16π/3

You are correct! Good job! I started this using the washer method and found that it was much more tedious than using the shell method, which worked very well and very easily. Very good work!

whose power in the senate is equal to the power of the speaker of the house?

step-by-step explanation:

a. 12.5 kg

step-by-step explanation:

f = ma

so

m = f/a = (2500 n)/(200 m/s²) = 12.5 kg

1 n = 1 kg·m/s²