Solve the inequality. show your work. |4r + 8| ≥ 32

|4r + 8| ≥ 32

Split this expression into two expressions:

First ⇒ 4r + 8 ≥ 32 and second ⇒ 4r + 8 ≤ - 32

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First expression: 4r + 8 ≥ 32

Subtract 8 from both sides.

4r ≥ 24

Divide both sides by 4.

r ≥ 6

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Second expression: 4r + 8 ≤ - 32

Subtract 8 from both sides.

4r ≤ -40

Divide both sides by 4.

r ≤ -10

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Your answer is

step-by-step explanation:

a rhombus is a parallelogram enjoying his symmetry.