25 points write the equation for the following relation. include all of your work in your final answer. submit your solution. r = {(x, y): (2, 3), (4, 4), (6, 5), (8, 6), . .}

R = {(x, y): (4, 5), (8, 7), (12, 9), (16, 11), . . .}

Notice that y increases by 2 when x increases by 4

slope = 2/4 = 1/2

Notice that if you decrease x by 4 y will decrease by 2

So, y-intercept = (0,3)

Equation: y = (1/2)x+3

R = {(x, y): (2, 3), (4, 4), (6, 5), (8, 6), . . .}

slope = 1/2

y-int: (0,1)

Equation: y = (1/2)x + 1

Q = {(x, y): (2, 8), (3, 27), (4, 64), (5, 125), . . .}

Not a linear relation because y does not increase consistently

as x increases.

Equation: y = x^3

P = {(x, y): (1, 0), (2, 4), (3, 8), (4, 12), . . .}

slope = 4

y-int: -4

Equation: y = 4x-4

can you rephrase the question ? it is unclear : -)

step-by-step explanation: