The winning times (in seconds) in a speed-skating event for men can be represented by the formula t = 46.12 - 0.094x where x represents the year, with x=0 corresponding to 1920. (for example in 1992, x would be 1992 - 1920 = 72.) according to the formula, what was the winning time in 1983? round to the nearest hundredth.

The given question is:

The winning times (in seconds) in a speed-skating event for men can be represented by the formula T = 46.12 - 0.094x where x represents the year, with x=0 corresponding to 1920.

In 1983,

Substituting 63 for x in the given equation, we will get

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine