Let g(x)=3x+2 and f(x)=x-2/3. find the value. g(f(2))

Let g(x)=3x+2 and f(x)=x-2/3

f(2) = 2 -2/3

f(2) = 6/3 - 2/3

f(2) = 4/3

g(f(2)) = 3(4/3) +2

g(f(2)) = 4 + 2

g(f(2)) = 6

Answer

6

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.