In triangle abc, the measure of angle b is 18° more than three times the measure of angle a. the measure of angle c is 42° more than the measure of angle a. find the measure of each angle.

A = A

B = 3A + 18

C = A + 42

The sum of the angles of a triangle equals 180°

A + B + C = 180

(A) + (3A + 18) + (A + 42) = 180

5A + 60 = 180

5A = 120

A = 24

B = 3A + 18 = 3(24) + 18 = 72 + 18 = 90

C = A + 42 = C = 24 + 42 = 66

A=24, B=90, C=66

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.

answer: i think one of the answer is $150 and $300?

step-by-step explanation: