What is an equation of the line that passes through the point (3,-7) and has a slope of -4/3

To solve the problem we can use the equation of a line that passes through a point and known slope:
y - y1 = m(x - x1)
where x1 and y1 represent the values of a point P(x1, y1) and m is the slope of the line. Then, we have:
P(3, -7)
m = -4/3
y - y1 = m(x - x1)
substituting:
y - (-7) = (-4/3)(x - 3)
y + 7 = (-4/3)x + 4
y = (-4/3)x - 3
that is the line equation in the form y = mx + b, where m is the slope, and b is the intercept (intersection) with the y axis