Find the smallest possible value of a quadratic equation

I'm assuming that you mean to find the minimum of a parabola, i.e. the minimum of a function defined as

To find the minimum of a function, we have to find a point such that

The first derivative is

The second derivative is

So, a parabola has a minimum only if (otherwise, the parabola is concave down and it has no lower bound). In that case, the minimum has coordinates

y = 3x+4

step-by-step explanation:

to find the slope

slope = (y2-y1)/ (x2-x1)

    = (-8-4)/ (-4-0)

    = -12/-4

  = 3

using the slope intercept form of a line

y= mx+b

we know the slope is 3

we know the y intercept is 4 ( the point where it crosses the y axis or x=0)

y = 3x+4

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step-by-step explanation: