How would you find the equation of a line that is perpendicular to y = 3x + 1 and passes through point (1, -1)?

perpendicular means the slopes of the two lines are opposite reciprocals. Since the slope of y = 3x + 1 is "3", then the opposite reciprocal slope is

Next, plug in the slope ( )and point (1, -1) into the point-slope formula: y - y₁ = m(x - x₁); where (x₁, y₁) is the point.

y - (-1) = (x - 1)

y + 1 = x +

y = x +

the equivalent expression are always the hardest ones but you look at the gcf also

step-by-step explanation:

i believe the answer is the polygon, heptagon.