Which powers have of value of 81. possible answers: 1^81, 3^4, 6^4, 9^2, 27^3.

1^81 is 1 multiplied by itself 81 times, which equals 1

3^4 is 3 multiplied by itself 4 times (3 x 3 x 3 x 3), which equals 81

6^4 is 6 multiplied by itself 4 times (6 x 6 x 6 x 6), which is 1296

9^2 is 9 multiplied by itself twice (9 x 9), which is 81

27^3 is 27 multiplied by itself 3 times (27 x 27 x 27), which is 19683.

3^4 and 9^2

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

-9

step-by-step explanation: