Snooker is a kind of pool or billiards played on a 6 foot by 12 foot table. the side pockets are half way down the rails . find the distance to the nearest tenth of a foot, diagonally across the table from the corner pocket to corner pocket

Let length be 12 ft (l = 12 ft) and width be 6 ft (w = 6ft).

The side pocket will be on the half of its length (l). To calculate the distance, we will use the distance d as a hypotenuse of the right triangle with sides w and l/2.

According to the Pythagorean theorem, the square of the hypotenuse is equal to the sum of the squares of two other sides:

d² = w² + (l/2)²

We have:

d = ?

w = 6 ft

l = 12 ft

d² = 6² + (12/2)²

d² = 6² + 6²

d²= 2 * 6²

d² = 2 * 36

d² = 72

d = √72

d = 8.48 ft

Since 1 ft is 12 in, then 8.48 ft is 101.76 in:

8.48 * 12 in = 101.76 in

Hope this helps!

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