The standard distance between studs in a house is 1.5 feet. if you have a set of blueprints for a house that mark every 1.5 feet with 3 in., by how many inches will a 53-foot wall be represented?

The applicable proportion is

... x/(53 ft) = (3 in)/(1.5 ft)

Multiplying by 53 ft gives

... x = (3 in)×(53 ft)/(1.5 ft)

... x = 106 in . . . . . . . . the length representing 53 ft

A 53-foot wall is going to be represented by 106 inches.

Step-by-step explanation:

This question can be solved as a simple rule of three problem.

The problem states that  you have a set of blueprints for a house that mark every 1.5 feet with 3 in. So, how many inches are there in 53 feet?

1.5 feet - 3 inches

53 feet - x inches

A 53-foot wall is going to be represented by 106 inches.

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.