Find the average rate of change of f of x equals 1 + sin x over the interval [0, pi/2]?

For every change in x, y changes 2/pi.

In order to find this we first need to evaluate the expression at the intervals.

x = 0

f(x) = 1 + sinx

f(0) = 1 + sin0

f(0) = 1 + 0

f(0) = 0

x = pi/2

f(x) = 1 + sinx

f(pi/2) = 1 + sin(pi/2)

f(pi/2) = 1 + 1

f(pi/2) = 2

So the total change in y is 1. So we divide that by how much x has changed in that interval to find the average rate of change.

1 / (pi/2) = 2/pi

i think there was a typo. you wrote pat brings 3 quarts of ice-cream to the party. each serving of ice-cream is 1 6 quart. how many total servings of ice-cream does pat bring to the party? i think the bold is supposed to be 1/6. so 1 quart of ice cream = 6 servings. 6 * 3 = 18.