In 1990, the population of area a was about 60 miltion. during the 1990s, the population of this area increased an average of about 0.4 million per year the population of area b was a bout 53 million in 1990. the population of this area increased an average of about 1 milion per year during the 1990s. assume that the rate of growth of these areas remains the same. estimate when the population of the area b would be equal to the population of the area a

The difference in population at the start of the decade is 60-53=7 million. The growth of Area B is 1-0.4 = 0.6 million per year faster than for Area A. Each year, the difference in population gets smaller by 0.6 million, so the difference of 7 million will disappear in 7/0.6 ≈ 11.7 years, late in the year 2001.

i think the answer is .36

step-by-step explanation:

what i did was only 2.88 divided by 8

15%

step-by-step explanation:

use the table and count the number of guesses that has two correct answers.

the following are two correct answers

10010, 01100, 11000

a total of 3 numbers having 2 correct guesses out of 20 questions.

probability of getting 2 correct guesses = the number of questions getting 2 correct answers / total number of questions.

= 3/20

to convert it into percent multiply by 100, we get

= 3/20 * 100

= 15%

the answer is 15%

you.