Mathematics, 12.07.2019 14:00 YmTia06221220
Will give ! find the inverse of the function. f(x) = 6x3 - 3 f-1(x) = cube root of quantity x minus three divided by six. f-1(x) = cube root of quantity x plus three divided by six. f-1(x) = cube root of x divided by six. + 3 not a one-to-one function
Answers: 1
![\text{now we will solve for y again and that will give the required inverse function.}\\ \text{so first we add 3 both sides to get}\\ \\ x+3=6y^3\\ \\ \text{now divide both sides by 6 to get}\\ \\ \frac{x+3}{6}=y^3\\ \\ \text{now take cube root both sides to get}\\ \\ \sqrt[3]{\frac{x+3}{6}}=\sqrt[3]{y^3}](/tpl/images/0081/1686/4dc8e.png)
![\Rightarrow \sqrt[3]{\frac{x+3}{6}}=y\\ \\ \Rightarrow y=\sqrt[3]{\frac{x+3}{6}}\\ \\ \text{hence the inverse of the function is: }\\ \\ f^{-1}(x)=\sqrt[3]{\frac{x+3}{6}}](/tpl/images/0081/1686/d4a14.png)
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Will give ! find the inverse of the function. f(x) = 6x3 - 3 f-1(x) = cube root of quantity x minus...
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