Atriangle has a perimeter of 160cm. side a is 5cm shorter than twice side b, and side c is 5cm longer than side b. find the length of each side.

B = x

A = 2x - 5

C = x + 5

The perimeter P = A + B + C and P = 160 cm

Substitute

(2x - 5) + x + (x + 5) = 160

(2x + x + x) + (-5 + 5) = 160

4x = 160 |:4

x = 40 cm

A = 2x - 5 → A = 2(40) - 5 = 75 cm

B = x → B = 40 cm

C = x + 5 → C = 40 + 5 = 45 cm

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

other answer is correct. i had used the radius of the radius somehow. a website: