Some me with this asap mike and his friends bought cheese wafers for $2 per packet and chocolate wafers for $1 per packet at a carnival. they spent a total of $25 to buy a total of 20 packets of wafers of the two varieties. part a: write a system of equations that can be solved to find the number of packets of cheese wafers and the number of packets of chocolate wafers that mike and his friends bought at the carnival. define the variables used in the equations. (5 points) part b: how many packets of chocolate wafers and cheese wafers did they buy? explain how you got the answer and why you selected a particular method to get the answer. (5 points)

A)

Let the cheese wafers be x and the chocolate wafers be y. You can formulate two systems of equations.

2x+y=25

x+y=20

where x=cheese and y=chocolate.

B)

Now, we have to solve for the solution and find the x and y values.

2x+y=25

x+y=20

We can use elimination.

2x+y=25

-x-y=-20

x=5

Now substitute 5 as x and find y.

x+y=20

5+y=20

y=15.

In conclusion, this suggests that Mike bought 5 packets of cheese wafers and 15 packets of chocolate wafers. I got the answer by using elimination as it is the easiest method in this format of the two equations.

Hope this helps

whatever you can spend with $11.53 or under.

step-by-step explanation:

20 - 8.47 = 11.53. take away the money he used for lunch from the starting amount of 20.

do you mean add both of the equations together

because if you do the answer is 10x-5

step-by-step explanation: