What is the initial value of the exponential function represented by the table? a. 1/8 b. 1/4 c. 1/2 d. 1 table x f(x) -2 1/8 -1 1/4 0 1/2 1 1 2 2

We are given

exponential function table

we can use exponential function formula

we know that

initial value is the value of f(x) when x=0

or initial value is value of y when x=0

we can see in the table

we are given

0 1/2

it means when x=0 then y=1/2

so, initial value is

so, option-C.......Answer

a function could be identified in 3 ways either on a chart,graph, or ordered pairs. first a function is that each point has its own. the rule is that there can be many x's to one y but there can not be 2 x's at different y's. so on a graph when you put a straight line through the y's there should be one dot only to be a function.

step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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