Suppose we toss a coin 4 times. how many different sequences of outcomes are possible if order matters? (for example, hhtt is one outcome and htht is counted as a different outcome)

Solution: Each coin toss has 2 possible outcomes "Head" and "Tail". So if we flip a coin four times, the number of possible outcomes are:

outcomes.

Let H denotes the Head and T denotes the Tail, then the 16 possible outcomes are enumerated below:

HHHH, HHHT, HHTH, HHTT, HTHH, HTHT, HTTH, HTTT,

THHH, THHT,  THTH, THTT,  TTHH,  TTHT, TTTH, TTTT

75

step-by-step explanation:

you do x-29=46 (the number of cantaloupes sold)

in order to find x, you have to find what minus 29 equals 46, meaning you'd have to add 29 to 46.

29+46=75

if you replace x with 75, the equation looks like:

75-29=46

x=75