Aballplayer catches a ball 3.4s after throwing it vertically upward. with what speed did he throw it, and what height did it reach

From the equation of motion, we know,

Where s= displacement

u= initial velocity

a= gravitational force

t= time

Displacement is 0 since the ball comes back to the same point from where it was thrown.  

A = since the ball is thrown upwards.

Plug the known values into the equation.

=>

Solving for u gives :

u= 16.67 m/ sec ....... equation (1)

At maximum height, final velocity i.e v is 0

Time take to reach the top =

=>

Solving for s we get

s= 14.16 m

the 2 figures are congruent bc if you reflect abcd over the y axis then over the d axis the figures overlap

step-by-step explanation: