The width of a rectangle is 15 cm less than the length. the perimeter is 78 cm. find the rectangle's dimensions

Length (L): L

width (w): L - 15

Perimeter (P) = 2L + 2w

                78 = 2(L) + 2(L - 15)

                78 = 2L + 2L - 30

                78 = 4L - 30

               108 = 4L

                27 = L

width (w): L - 15   = 27 - 15   = 12

width = 12 cm, length = 27 cm

idk

step-by-step explanation:

maybe try   if it is work from a book, if not try

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.