Ahoneybee flaps its wings 200 times per second. how much time is required for one wingbeat? give your answere in millisecond

The time required for one wing beat is 5 milliseconds.

Explanation

Lets assume, the time required for one wing beat is   seconds

So, the time required for 200 wing beat seconds

Given that, the honeybee flaps its wings 200 times per 1 second. So...

So, the time required for one wing beat is 5 milliseconds.

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation:

fwms@lil_ben06

step-by-step explanation: