Find the zeros of g(x) = -x^2 + 6x - 8

(Remember to set g(x) to zero).

For this, I will be completing the square. Firstly, what two terms have a product of 8x^2 and a sum of 6x? That would be 4x and 2x. Replace 6x with 2x + 4x:

Next, factor -x^2 + 2x and 4x - 8 separately. Make sure that they have the same quantity on the inside of the parentheses:

Next, you can rewrite the equation as

Now apply the Zero Product Property:

The zeros of this equation are 4 and 2.

dont understand

step-by-step explanation:

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step-by-step explanation:

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