What is the volume of a right cone with a radius of 10 and a height of 13.5?

a right circular cone with radius 10 cm and height 9 cm

the volume

The volume of a right circular cone of radius r and height h is given by the formula

... V = (1/3)π·r²·h

For the given cone, this evaluates to

... V = (1/3)π·(10 cm)²·(9 cm) = 300π cm³ ≈ 942.5 cm³

Note that the 13.5 cm dimension is the slant height, useful for finding the surface area, but not for finding volume. The perpendicular distance from the base to the  apex (9 cm) is the height of interest for volume purposes.

-7

step-by-step explanation:

x^2 + 18x + 74 = (x + 9)^2 - 81 + 74

= (x + 9)^2 - 7.

so q = -7.

we have three similar triangles, because each has a right angle and shares an angle.   let's write the angles in order: opposite to short leg, long leg, hypotenuse.

cab similar to bad similar to cbd

or as ratios,

ca: ab: cb = ba: ad: bd = cb: bd: cd

we also know

ac = ad + cd

(ad+cd): ab: cb = ba: ad: bd = cb: bd: cd

(ad+cd)/cb=cb/cd

we have cb=6, ad=5 and seek x=cd.

we reject the negative root and conclude x=4

answer: 4