Mathematics, 11.07.2019 17:30 madisonrendler1787
Asap i need will give extra point given that f(x) = x^2+3x -5 and g(x)= x +4 find g(f(x)) when x = 1
Answers: 2
![\bf \begin{cases} f(x)=x^2+3x-5\\ g(x)=x+4 \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{x=1}{f(1)}=(1)^2+3(1)-5\implies \boxed{f(1)}=-1 \\\\[-0.35em] ~\dotfill\\\\ g(~~f(x)~~)=[f(x)]+4\implies g(~~f(1)~~)=[f(1)]+4 \\\\\\ g(~~f(1)~~)=\boxed{-1}+4\implies \blacktriangleright g(~~f(1)~~)=3 \blacktriangleleft](/tpl/images/0077/8875/19d49.png)
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Asap i need will give extra point given that f(x) = x^2+3x -5 and g(x)= x +4 find g(f(x)) when x =...
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