If the perimeter of a rectangle is 140 meters and the length is 5 meters less than 4 times the width, then what are the dimensions of the rectangle

Length (L): 4w - 5

width (w): w

Perimeter (P) = 2L + 2w

              140 = 2(4w - 5) + 2(w)

              140 = 8w - 10 + 2w

              140 = 10w - 10

               150 = 10w

                15 = w

Length (L): 4w - 5   = 4(15) - 5   = 60 - 5   = 55

width= 15meters, length=55 meters

55

step-by-step explanation:

answer: the answer is one of

step-by-step explanation:   we are given to write a proper fraction where the whole is divided into an even number of equal parts less than ten, and an odd number of those parts exist.

an even number less than 10 may be one of 2, 4, 6 or 8. so, the whole may be one of these four evens.

now, an odd number of these parts must exist, so the numerator must be an odd number, one of 1, 3, 5 or 7. it cannot be 9 because then the fraction will become improper.

thus, our fraction may be one of the following