Jack and jill exercise in a 25.0-m-long swimming pool. jack swims nine lengths of the pool in 2 minutes and 32.1 seconds, while jill, the faster swimmer, covers ten lengths in the same time interval. find the average velocity and average speed of each swimmer.

Average Speed

Jack swims nine lengths of a 25 meter long swimming pool in 2 minutes and 32.1 seconds.

So, total distance and time

Thus, average speed of Jack

Now, Jill swims ten lengths of the 25 meter long swimming pool in the same time interval.

So, the total distance and time

Thus, average speed of Jill

Average Velocity

As Jack swims nine lengths of the pool, it means he ends up at the opposite end of the pool from where he started.  So, the net displacement = 25 meter

Thus, average velocity of Jack

Now, Jill swims ten length of the pool, it means he ends up at the starting position. So, the net displacement = 0 meter

Thus, average velocity of Jill meter/second.

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15